Question

decide whether these proposed lewis structures are reasonable.
proposed lewis structure is the proposed lewis structure reasonable?
yes.
no, it has the wrong number of valence electrons.
the correct number is:
no, it has the right number of valence electrons but doesnt satisfy the octet rule.
the symbols of the problem atoms are: *
yes.
no, it has the wrong number of valence electrons.
the correct number is:
no, it has the right number of valence electrons but doesnt satisfy the octet rule.
the symbols of the problem atoms are: *
yes.
no, it has the wrong number of valence electrons.
the correct number is:
no, it has the right number of valence electrons but doesnt satisfy the octet rule.
the symbols of the problem atoms are: *

• if two or more atoms of the same element dont satisfy the octet rule, just enter the chemical symbol as many times as necessary. for example, if two oxygen atoms dont satisfy the octet rule, enter \o,o\.

Explanation:

Step1: Calculate valence - electrons for CO

Carbon has 4 valence electrons and oxygen has 6 valence electrons. So the total number of valence electrons for CO is \(4 + 6=10\). The given Lewis - structure of CO has 10 valence electrons (\(2\) bonding pairs and \(3\) non - bonding pairs on oxygen and \(1\) non - bonding pair on carbon). Also, both C and O satisfy the octet rule.

Step2: Calculate valence - electrons for \(N_3^-\)

Nitrogen has 5 valence electrons. For \(N_3^-\), the total number of valence electrons is \(3\times5 + 1=16\). In the given Lewis - structure of \(N_3^-\), the number of valence electrons is \(2\) bonding pairs between the left and middle N, \(3\) bonding pairs between the middle and right N, and \(2\) non - bonding pairs on the left N and \(1\) non - bonding pair on the right N, which sums up to 16. And all nitrogen atoms satisfy the octet rule.

Step3: Calculate valence - electrons for \(CO_2\)

Carbon has 4 valence electrons and each oxygen has 6 valence electrons. So the total number of valence electrons for \(CO_2\) is \(4+2\times6 = 16\). The given Lewis - structure of \(CO_2\) has only 12 valence electrons (\(2\) bonding pairs between C and each O and \(2\) non - bonding pairs on each O). The correct number of valence electrons is 16.

Answer:

1. Yes.
2. Yes.
3. No, it has the wrong number of valence electrons. The correct number is: 16.