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a mixture of ethyl alcohol (molecular mass = 46.1 u) and water (molecular mass = 18.0 u) contains one mole of molecules. the mixture contains 18.8 g of ethyl alcohol. what mass m of water does it contain?
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Explanation:

Step1: Calculate moles of ethyl alcohol

Moles of ethyl alcohol, \( n_{ethanol} = \frac{mass}{molar\ mass} = \frac{18.8\ g}{46.1\ g/mol} \approx 0.4078\ mol \)

Step2: Determine moles of water

Total moles of molecules = 1 mol. So moles of water, \( n_{water} = 1 - n_{ethanol} = 1 - 0.4078 = 0.5922\ mol \)

Step3: Calculate mass of water

Mass of water, \( m = n_{water} \times molar\ mass_{water} = 0.5922\ mol \times 18.0\ g/mol \approx 10.66\ g \)

Answer:

10.7 (approximate, or more precise 10.66) grams