Question

1. _ c + _ s₈ → ___ cs₂
2. _ na + _ o → ___ na₂o

Explanation:

Step1: Balance sulfur atoms

In \(S_8\) and \(CS_2\), to balance sulfur, since there are 8 sulfur atoms in \(S_8\) and 2 in \(CS_2\), we put 4 in front of \(CS_2\) (because \(8\div2 = 4\)). So the equation becomes \(C+S_8
ightarrow4CS_2\).

Step2: Balance carbon atoms

Now, for carbon, there is 1 carbon atom on the left and 4 on the right. So we put 4 in front of \(C\). The balanced equation is \(4C + S_8
ightarrow4CS_2\).

Step3: Balance oxygen atoms (for the second equation)

In \(Na + O
ightarrow Na_2O\), there is 1 oxygen atom on the left and 1 on the right. For sodium, there is 1 on the left and 2 on the right. So we put 2 in front of \(Na\). The balanced equation is \(2Na+O
ightarrow Na_2O\).

Answer:

1. \(4C + S_8

ightarrow4CS_2\)

1. \(2Na+O

ightarrow Na_2O\)