Question

correct. torr is the given unit of pressure in this problem. correct. kelvin (k) is the given unit of temperature in this problem. incorrect. this is the unknown variable. enter a question mark (?) to indicate this. calculate the value of the unknown variable. include the calculated value on the left and use the drop - down menu to choose the correct unit. did i get this a sample of oxygen gas is in a fixed container of 250.0 ml at a temperature of 25.0 °c. the pressure is measured and found to be 102.6 kpa. if the sample is heated to 75.0 °c, what is the new pressure? 87.8 kpa 34.2 kpa 308 kpa 120 kpa

Explanation:

Step1: Convert Celsius to Kelvin

For initial temperature: \(T_1 = 25.0^{\circ}C+273.15 = 298.15\space K\)
For final temperature: \(T_2=75.0^{\circ}C + 273.15=348.15\space K\)

Step2: Apply Gay - Lussac's Law (\(P_1/T_1=P_2/T_2\))

Given \(P_1 = 102.6\space kPa\), \(T_1 = 298.15\space K\), \(T_2 = 348.15\space K\)
We can solve for \(P_2\):

$$P_2=\frac{P_1\times T_2}{T_1}$$

$$P_2=\frac{102.6\times348.15}{298.15}$$

$$P_2=\frac{102.6\times348.15}{298.15}\approx120\space kPa$$

Answer:

120 kPa