Question

1. convert 6.74x10²⁴ molecules of glucose (c₆h₁₂o₆) into moles:
2. how many molecules are in 7.24 moles of carbon monoxide?

Explanation:

Step1: Use the formula \( n=\frac{N}{N_A} \) for question 6

Where \( N = 6.74\times10^{24}\) molecules and \( N_A=6.022\times 10^{23}\text{ molecules/mol}\)
\( n=\frac{6.74\times 10^{24}}{6.022\times 10^{23}}\)

Step2: Calculate the value for question 6

\( n=\frac{6.74}{6.022}\times10^{24 - 23}\approx11.2\) mol

Step3: Use the formula \( N=n\times N_A\) for question 7

Where \( n = 7.24\) mol and \( N_A = 6.022\times10^{23}\text{ molecules/mol}\)
\( N=7.24\times6.022\times 10^{23}\)

Step4: Calculate the value for question 7

\( N=(7.24\times6.022)\times10^{23}\approx4.36\times 10^{24}\) molecules

Answer:

1. Approximately \( 11.2\) mol
2. Approximately \( 4.36\times 10^{24}\) molecules