Question

construct the expression for kb for the weak base, n₂h₄.
n₂h₄(aq) + h₂o(l) ⇌ oh⁻(aq) + n₂h₅⁺(aq)
based on the definition of kb, drag the tiles into the numerator or denominator to construct the expression for the given base.
kb =
reset
h₂o h₃o⁺ oh⁻ n₂h₅⁺ n₂h₄ n₂h₅⁻ 2h₂o 2h₃o⁺
2oh⁻ 2n₂h₅⁺ 2n₂h₄ 2n₂h₅⁻ h₂o² h₃o⁺² oh⁻² n₂h₅⁺²
n₂h₄² n₂h₅⁻²

Explanation:

Step1: Recall the formula for \(K_b\)

For a general base dissociation reaction \(B + H_2O
ightleftharpoons BH^+ + OH^-\), \(K_b=\frac{[BH^+][OH^-]}{[B]}\)

Step2: Identify the species in the given reaction

In \(N_2H_4(aq)+H_2O(l)
ightleftharpoons OH^-(aq)+N_2H_5^+(aq)\), \(B = N_2H_4\), \(BH^+=N_2H_5^+\)

Answer:

Numerator: \([OH^-][N_2H_5^+]\)
Denominator: \([N_2H_4]\)