Question

consider the unbalanced equation for the oxidation of aluminum. _al + _o₂ → _al₂o₃ which sequence of coefficients should be placed in the blanks to balance this equation? 2, 3, 1 1, 3, 2 4, 3, 2 3, 2, 3

Explanation:

Step1: Balance oxygen atoms

The least - common multiple of \(2\) (from \(O_2\)) and \(3\) (from \(Al_2O_3\)) is \(6\).
For \(O_2\): If \(O\) in \(O_2\) gives \(6\) \(O\) atoms, then the coefficient of \(O_2\) is \(\frac{6}{2}=3\).
For \(Al_2O_3\): If \(O\) in \(Al_2O_3\) gives \(6\) \(O\) atoms, then the coefficient of \(Al_2O_3\) is \(\frac{6}{3}=2\).

Step2: Balance aluminum atoms

Since the coefficient of \(Al_2O_3\) is \(2\), which has \(2\times2 = 4\) \(Al\) atoms. So the coefficient of \(Al\) is \(4\).

Answer:

\(4,3,2\)