consider the reaction:
bf₃ + ncl₃ → f₃b - ncl₃
part 1 of 2
what changes in hybridization (if any) of the b atom are a result of this reaction? check all that apply.
before the reaction boron is sp² hybridized, and after the reaction it is sp³d² hybridized.
before the reaction boron is sp³ hybridized, and after the reaction it is sp³d hybridized.
before the reaction boron is sp³ hybridized, and after the reaction it is sp³d² hybridized.
none of the above.
part 2 of 2
what changes in hybridization (if any) of the n atom are a result of this reaction? check all that apply.
before the reaction nitrogen is sp² hybridized, and after the reaction it is sp hybridized.
before the reaction nitrogen is sp³ hybridized, and after the reaction it is sp hybridized.
before the reaction nitrogen is sp³ hybridized, and after the reaction it is sp³ hybridized.
none of the above.

Question

Accepted Answer

# Brief Explanations:
- **For $B$ atom**:
    - In $BF_3$, $B$ has $3$ bonding pairs and $0$ lone pairs. Using the formula $\text{hybridization}=\text{number of bonding pairs}+\text{number of lone pairs}$, for $BF_3$, $\text{hybridization}=3 + 0=3$. According to the hybridization rules ($sp^2$ when the sum is $3$), $B$ is $sp^2$ hybridized.
    - In $F_3B - NCl_3$, $B$ has $4$ bonding pairs (three $B - F$ and one $B - N$ bond) and $0$ lone pairs. So, $\text{hybridization}=4+0 = 4$, and $B$ is $sp^3$ hybridized.
- **For $N$ atom**:
    - In $NCl_3$, $N$ has $3$ bonding pairs ($N - Cl$ bonds) and $1$ lone pair. So, $\text{hybridization}=3 + 1=4$, and $N$ is $sp^3$ hybridized.
    - In $F_3B - NCl_3$, $N$ still has $3$ bonding pairs ($N - Cl$ bonds) and $1$ lone pair (the lone pair on $N$ is now used to form a coordinate - covalent bond with $B$, but the electron - pair geometry around $N$ is still based on $4$ electron pairs). So, $\text{hybridization}=3+1 = 4$, and $N$ is $sp^3$ hybridized.

# Answer:
- Part 1 of 2: None of the above.
- Part 2 of 2: Before the reaction nitrogen is $sp^3$ hybridized, and after the reaction it is $sp^3$ hybridized.

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Answer: