Question

consider an isotope of carbon that has 7 neutrons. (6 pt)

1. write this isotopes notation in nuclear form.
2. write this isotopes notation in hyphen form.

Explanation:

Step1: Find the mass number

The atomic number of carbon (\(C\)) is \(6\) (number of protons). The mass number (\(A\)) is the sum of protons (\(p\)) and neutrons (\(n\)). Given \(n = 7\) and \(p=6\), then \(A=p + n=6 + 7 = 13\).

Step2: Write the nuclear - form notation

The nuclear - form notation for an isotope is \(\ce{^{A}_{Z}X}\), where \(Z\) is the atomic number, \(A\) is the mass number, and \(X\) is the element symbol. For carbon (\(Z = 6\), \(A = 13\)), the nuclear - form notation is \(\ce{^{13}_{6}C}\).

Step3: Write the hyphen - form notation

The hyphen - form notation is element - mass number. For carbon with mass number \(13\), it is carbon - 13.

Answer:

a. \(\ce{^{13}_{6}C}\)
b. carbon - 13