Question

consider the following reversible reaction.

2h₂o(g) ⇌ 2h₂(g) + o₂(g)

what is the equilibrium constant expression for the given system?

○ kₑq = h₂o/h₂o₂

○ kₑq = h₂o²/h₂²o₂

○ kₑq = h₂²o₂/h₂o

○ kₑq = h₂²o₂/h₂o²

Explanation:

Step1: Recall the formula for equilibrium constant

For a general reaction \(aA + bB
ightleftharpoons cC + dD\), the equilibrium constant \(K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}\), where \([X]\) represents the molar concentration of species \(X\).

Step2: Identify the coefficients in the given reaction

In the reaction \(2H_2O(g)
ightleftharpoons 2H_2(g)+O_2(g)\), \(a = 2\) (for \(H_2O\)), \(c = 2\) (for \(H_2\)) and \(d=1\) (for \(O_2\)).

Step3: Substitute into the formula

Substituting the values into the \(K_{eq}\) formula, we get \(K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}\).

Answer:

\(K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}\) (the last option)