QUESTION IMAGE
Question
complete the sentences to explain why co₂ and ccl₄ are both nonpolar even though they contain polar bonds. match the words in the left column to the appropriate blanks in the sentences on the right. zero one two three four linear trigonal planar tetrahedral trigonal pyramidal bonds are only slightly polar given the lewis structure of co₂, the central carbon atom has lone pair(s) of electrons and total electron groups. thus the molecular geometry is. given the lewis structure of ccl₄, the central carbon atom has lone pair(s) of electrons and total electron groups. thus the molecular geometry is. the reason both molecules are nonpolar is best explained because the.
Step1: Analyze \( \ce{CO2} \) Lewis Structure
The Lewis structure of \( \ce{CO2} \) is \( \ce{O=C=O} \). The central \( \ce{C} \) atom has 0 lone pairs (since it forms double bonds with two \( \ce{O} \) atoms, using all its valence electrons for bonding). The total electron groups around \( \ce{C} \) are 2 (two double bonds, each counted as one electron group). For a central atom with 0 lone pairs and 2 electron groups, the molecular geometry is linear. So the blanks for \( \ce{CO2} \) are "zero", "two", "linear".
Step2: Analyze \( \ce{CCl4} \) Lewis Structure
The Lewis structure of \( \ce{CCl4} \) has the central \( \ce{C} \) atom bonded to four \( \ce{Cl} \) atoms (single bonds). So the central \( \ce{C} \) has 0 lone pairs (all valence electrons used in bonding) and 4 total electron groups (four single bonds). For a central atom with 0 lone pairs and 4 electron groups, the molecular geometry is tetrahedral. So the blanks for \( \ce{CCl4} \) are "zero", "four", "tetrahedral".
Step3: Explain Nonpolarity Reason
The reason both molecules are nonpolar is that the polar bonds are arranged symmetrically (linear for \( \ce{CO2} \), tetrahedral for \( \ce{CCl4} \)), so the bond dipoles cancel out, resulting in a net dipole moment of zero. But from the given options (assuming the last option related to symmetry, but based on the left column, the correct phrase for the last blank would be about the symmetric arrangement causing bond dipoles to cancel, but from the left column words, the relevant part is that the molecular geometries lead to symmetric distribution, but the left column has "bonds are only slightly polar" is incorrect. Wait, the correct reason is that the polar bonds are arranged symmetrically so their dipoles cancel. But from the left column, the words given: the last blank should be explained by the symmetric geometry (linear and tetrahedral) leading to net dipole zero. But the left column words: let's re - check. The left column has "zero", "one", "two", "three", "four", "linear", "trigonal planar", "tetrahedral", "trigonal pyramidal", "bonds are only slightly polar". The correct reason for nonpolarity is that the polar bonds are arranged in a symmetric geometry (linear for \( \ce{CO2} \), tetrahedral for \( \ce{CCl4} \)) so that the bond dipoles cancel. But from the left column, the appropriate phrase (if we consider the options) – but the last blank: the reason is that the polar bonds are symmetrically arranged, so their dipole moments cancel. But the left column has "bonds are only slightly polar" is wrong. Wait, maybe the last blank is about the symmetric arrangement. But based on the left column words, the correct filling for the last sentence: the reason both molecules are nonpolar is best explained because the (polar bonds are arranged symmetrically, but from the left column, the words given – maybe the intended answer is that the bond dipoles cancel due to symmetric geometry. But from the left column, the available words: let's see, the last blank – the correct concept is that the polar bonds are symmetrically arranged (linear and tetrahedral) so net dipole is zero. But the left column has "bonds are only slightly polar" is incorrect. Wait, maybe the last blank is supposed to be filled with the idea that the symmetric geometry causes the bond dipoles to cancel, but from the left column, the words: maybe the intended answer is related to the symmetric arrangement. But let's proceed with the blanks:
For \( \ce{CO2} \):
- Central \( \ce{C} \) lone pairs: zero
- Total electron groups: two
- Molecular geometry…
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For \( \ce{CO2} \) blanks: zero, two, linear.
For \( \ce{CCl4} \) blanks: zero, four, tetrahedral.
The reason both molecules are nonpolar is best explained because the (polar bonds are arranged symmetrically, so their dipoles cancel, resulting in a net dipole moment of zero. But from the given left - column words, the relevant part is that the molecular geometries (linear and tetrahedral) lead to the symmetric arrangement of polar bonds, causing bond dipoles to cancel. However, if we have to use the left - column words, the incorrect option "bonds are only slightly polar" is wrong. The correct concept is symmetric arrangement of polar bonds.