1 ___h₂ + ___cl₂ → ___hcl
2 ___c₃h₈ + ___o₂ → ___co₂ + ___h₂o
3. ___zn + ___cuso₄ → ___znso₄ + ___cu
4. ___kclo₃ → ___kcl + ___o₂
5 ___fe + ___o₂ → ___fe₂o₃
6. ___na₂co₃ + ___hcl → ___nacl + ___h₂o + ___co₂
7. ___ca + ___h₂o → ___ca(oh)₂ + ___h₂
8. ___al + ___o₂ → ___al₂o₃
9. ___h₂o₂ → ___h₂o + ___o₂
10. ____ch₄ + ___o₂ → ___co₂ + ___h₂o
11. ___agno₃ + ___nacl → ___agcl + ____nano₃
12. ___mg + ___hcl → ___mgcl₂ + ___h₂
13. ___nh₃ + ____o₂ → ___no + ____h₂o
14. ____na + ___cl₂ → ___nacl
15. ____caco₃ → ____cao + ____co₂

Question

Accepted Answer

# Explanation:
## Step1: Balance hydrogen and chlorine atoms
For the reaction $H_{2}+Cl_{2}\to HCl$, there are 2 hydrogen atoms and 2 chlorine atoms on the left - hand side. On the right - hand side, for $HCl$, to balance the atoms, we need 2 moles of $HCl$. So the balanced equation is $1H_{2}+1Cl_{2}\to2HCl$

## Step2: Balance carbon, hydrogen and oxygen atoms for $C_{3}H_{8}+O_{2}\to CO_{2}+H_{2}O$
- **Carbon balance**: There are 3 carbon atoms in $C_{3}H_{8}$, so we need 3 moles of $CO_{2}$ ($C_{3}H_{8}+O_{2}\to3CO_{2}+H_{2}O$)
- **Hydrogen balance**: There are 8 hydrogen atoms in $C_{3}H_{8}$, so we need 4 moles of $H_{2}O$ ($C_{3}H_{8}+O_{2}\to3CO_{2}+4H_{2}O$)
- **Oxygen balance**: On the right - hand side, there are $3\times2 + 4\times1=6 + 4 = 10$ oxygen atoms. So we need 5 moles of $O_{2}$. The balanced equation is $1C_{3}H_{8}+5O_{2}\to3CO_{2}+4H_{2}O$

## Step3: Balance zinc, copper, sulfur and oxygen atoms for $Zn + CuSO_{4}\to ZnSO_{4}+Cu$
The number of zinc ($Zn$), copper ($Cu$), sulfur ($S$) and oxygen ($O$) atoms is already balanced. So the balanced equation is $1Zn + 1CuSO_{4}\to1ZnSO_{4}+1Cu$

## Step4: Balance potassium, chlorine and oxygen atoms for $KClO_{3}\to KCl+O_{2}$
- **Oxygen balance**: Let the coefficient of $KClO_{3}$ be $2$ (to make the number of oxygen atoms even). Then we have $2KClO_{3}\to KCl + O_{2}$. After balancing oxygen ($2KClO_{3}\to KCl+3O_{2}$), balance potassium and chlorine. The balanced equation is $2KClO_{3}\to2KCl + 3O_{2}$

## Step5: Balance iron and oxygen atoms for $Fe+O_{2}\to Fe_{2}O_{3}$
- **Oxygen balance**: The least common multiple of 2 (from $O_{2}$) and 3 (from $Fe_{2}O_{3}$) is 6. So we need $3O_{2}$ and $2Fe_{2}O_{3}$ ($Fe + 3O_{2}\to2Fe_{2}O_{3}$)
- **Iron balance**: Then we need 4 moles of $Fe$. The balanced equation is $4Fe+3O_{2}\to2Fe_{2}O_{3}$

## Step6: Balance sodium, carbon, hydrogen, chlorine and oxygen atoms for $Na_{2}CO_{3}+HCl\to NaCl+H_{2}O + CO_{2}$
- **Sodium balance**: There are 2 sodium atoms in $Na_{2}CO_{3}$, so we need 2 moles of $NaCl$ ($Na_{2}CO_{3}+HCl\to2NaCl+H_{2}O + CO_{2}$)
- **Chlorine balance**: Then we need 2 moles of $HCl$. The balanced equation is $1Na_{2}CO_{3}+2HCl\to2NaCl + 1H_{2}O+1CO_{2}$

## Step7: Balance calcium, hydrogen and oxygen atoms for $Ca + H_{2}O\to Ca(OH)_{2}+H_{2}$
- **Calcium balance**: Already balanced (1 mole of $Ca$)
- **Oxygen balance**: There are 2 oxygen atoms in $Ca(OH)_{2}$, so we need 2 moles of $H_{2}O$ ($Ca+2H_{2}O\to Ca(OH)_{2}+H_{2}$)
- **Hydrogen balance**: On the left - hand side, there are 4 hydrogen atoms ($2H_{2}O$), on the right - hand side, there are $2 + 2=4$ hydrogen atoms ($Ca(OH)_{2}$ has 2 and $H_{2}$ has 2). The balanced equation is $1Ca+2H_{2}O\to1Ca(OH)_{2}+1H_{2}$

## Step8: Balance aluminium and oxygen atoms for $Al+O_{2}\to Al_{2}O_{3}$
- **Oxygen balance**: The least common multiple of 2 (from $O_{2}$) and 3 (from $Al_{2}O_{3}$) is 6. So we need $3O_{2}$ and $2Al_{2}O_{3}$ ($Al+3O_{2}\to2Al_{2}O_{3}$)
- **Aluminium balance**: Then we need 4 moles of $Al$. The balanced equation is $4Al + 3O_{2}\to2Al_{2}O_{3}$

## Step9: Balance hydrogen and oxygen atoms for $H_{2}O_{2}\to H_{2}O+O_{2}$
- **Oxygen balance**: Let the coefficient of $H_{2}O_{2}$ be 2. Then $2H_{2}O_{2}\to H_{2}O+O_{2}$. After balancing oxygen ($2H_{2}O_{2}\to2H_{2}O+1O_{2}$). The balanced equation is $2H_{2}O_{2}\to2H_{2}O+1O_{2}$

## Step10: Balance carbon, hydrogen and oxygen atoms for $CH_{4}+O_{2}\to CO_{2}+H_{2}O$
- **Carbon balance**: 1 mole of $CH_{4}$ gives 1 mole of $CO_{2}$ ($CH_{4}+O_{2}\to1CO_{2}+H_{2}O$)
- **Hydrogen balance**: 4 hydrogen atoms in $CH_{4}$ give 2 moles of $H_{2}O$ ($CH_{4}+O_{2}\to1CO_{2}+2H_{2}O$)
- **Oxygen balance**: 4 oxygen atoms on the right - hand side, so we need 2 moles of $O_{2}$. The balanced equation is $1CH_{4}+2O_{2}\to1CO_{2}+2H_{2}O$

## Step11: Balance silver, nitrogen, oxygen, sodium and chlorine atoms for $AgNO_{3}+NaCl\to AgCl+NaNO_{3}$
The number of silver ($Ag$), nitrogen ($N$), oxygen ($O$), sodium ($Na$) and chlorine ($Cl$) atoms is already balanced. So the balanced equation is $1AgNO_{3}+1NaCl\to1AgCl+1NaNO_{3}$

## Step12: Balance magnesium, hydrogen and chlorine atoms for $Mg+HCl\to MgCl_{2}+H_{2}$
- **Chlorine balance**: There are 2 chlorine atoms in $MgCl_{2}$, so we need 2 moles of $HCl$ ($Mg + 2HCl\to MgCl_{2}+H_{2}$)
- **Hydrogen balance**: Already balanced. The balanced equation is $1Mg+2HCl\to1MgCl_{2}+1H_{2}$

## Step13: Balance nitrogen, hydrogen and oxygen atoms for $NH_{3}+O_{2}\to NO+H_{2}O$
- **Hydrogen balance**: Let the coefficient of $NH_{3}$ be 4. Then $4NH_{3}+O_{2}\to NO+H_{2}O$. There are 12 hydrogen atoms, so we need 6 moles of $H_{2}O$ ($4NH_{3}+O_{2}\to NO+6H_{2}O$)
- **Nitrogen balance**: 4 moles of $NH_{3}$ give 4 moles of $NO$ ($4NH_{3}+O_{2}\to4NO+6H_{2}O$)
- **Oxygen balance**: On the right - hand side, there are $4 + 6=10$ oxygen atoms. So we need 5 moles of $O_{2}$. The balanced equation is $4NH_{3}+5O_{2}\to4NO+6H_{2}O$

## Step14: Balance sodium and chlorine atoms for $Na+Cl_{2}\to NaCl$
- **Chlorine balance**: There are 2 chlorine atoms in $Cl_{2}$, so we need 2 moles of $NaCl$ ($Na+Cl_{2}\to2NaCl$)
- **Sodium balance**: Then we need 2 moles of $Na$. The balanced equation is $2Na+1Cl_{2}\to2NaCl$

## Step15: Balance calcium, carbon and oxygen atoms for $CaCO_{3}\to CaO+CO_{2}$
The number of calcium ($Ca$), carbon ($C$) and oxygen ($O$) atoms is already balanced. So the balanced equation is $1CaCO_{3}\to1CaO+1CO_{2}$

# Answer:
1. $1H_{2}+1Cl_{2}\to2HCl$
2. $1C_{3}H_{8}+5O_{2}\to3CO_{2}+4H_{2}O$
3. $1Zn + 1CuSO_{4}\to1ZnSO_{4}+1Cu$
4. $2KClO_{3}\to2KCl + 3O_{2}$
5. $4Fe+3O_{2}\to2Fe_{2}O_{3}$
6. $1Na_{2}CO_{3}+2HCl\to2NaCl + 1H_{2}O+1CO_{2}$
7. $1Ca+2H_{2}O\to1Ca(OH)_{2}+1H_{2}$
8. $4Al + 3O_{2}\to2Al_{2}O_{3}$
9. $2H_{2}O_{2}\to2H_{2}O+1O_{2}$
10. $1CH_{4}+2O_{2}\to1CO_{2}+2H_{2}O$
11. $1AgNO_{3}+1NaCl\to1AgCl+1NaNO_{3}$
12. $1Mg+2HCl\to1MgCl_{2}+1H_{2}$
13. $4NH_{3}+5O_{2}\to4NO+6H_{2}O$
14. $2Na+1Cl_{2}\to2NaCl$
15. $1CaCO_{3}\to1CaO+1CO_{2}$

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QUESTION IMAGE

Question

Explanation:

Step1: Balance hydrogen and chlorine atoms

Step2: Balance carbon, hydrogen and oxygen atoms for \(C_{3}H_{8}+O_{2}\to CO_{2}+H_{2}O\)

Step3: Balance zinc, copper, sulfur and oxygen atoms for \(Zn + CuSO_{4}\to ZnSO_{4}+Cu\)

Step4: Balance potassium, chlorine and oxygen atoms for \(KClO_{3}\to KCl+O_{2}\)

Step5: Balance iron and oxygen atoms for \(Fe+O_{2}\to Fe_{2}O_{3}\)

Step6: Balance sodium, carbon, hydrogen, chlorine and oxygen atoms for \(Na_{2}CO_{3}+HCl\to NaCl+H_{2}O + CO_{2}\)

Step7: Balance calcium, hydrogen and oxygen atoms for \(Ca + H_{2}O\to Ca(OH)_{2}+H_{2}\)

Step8: Balance aluminium and oxygen atoms for \(Al+O_{2}\to Al_{2}O_{3}\)

Step9: Balance hydrogen and oxygen atoms for \(H_{2}O_{2}\to H_{2}O+O_{2}\)

Step10: Balance carbon, hydrogen and oxygen atoms for \(CH_{4}+O_{2}\to CO_{2}+H_{2…

Answer: