Question

choose the larger atom from each pair.
match the items in the left column to the appropriate blanks in the sentences on the right.
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si
when comparing the two elements te and br, the larger element is based on
periodic trends alone.
c
cl
when comparing the two elements cl and mg, the larger element is based on
periodic trends alone.
ti
mg
when comparing the two elements si and ti, the larger element is based on periodic
trends alone.
br
sn
when comparing the two elements sn and c, the larger element is based on periodic
trends alone.
impossible to determine
te

Explanation:

• For \(Te\) and \(Br\): Atomic radius increases down a group and decreases across a period. \(Te\) is in period 5 and group 16, while \(Br\) is in period 4 and group 17. Since \(Te\) is in a lower period (has more electron shells), it has a larger atomic radius.
• For \(Cl\) and \(Mg\): In the same period (period 3), atomic radius decreases from left to right. \(Mg\) is to the left of \(Cl\) in period 3, so \(Mg\) has a larger atomic radius.
• For \(Si\) and \(Tl\): \(Tl\) is in period 6 and group 13, while \(Si\) is in period 3 and group 14. \(Tl\) has more electron shells (lower in the periodic table), so \(Tl\) has a larger atomic radius.
• For \(Sn\) and \(C\): \(Sn\) is in period 5 and group 14, \(C\) is in period 2 and group 14. \(Sn\) has more electron shells (lower in the group), so \(Sn\) has a larger atomic radius.

Answer:

When comparing the two elements \(Te\) and \(Br\), the larger element is \(Te\) based on periodic trends alone.
When comparing the two elements \(Cl\) and \(Mg\), the larger element is \(Mg\) based on periodic trends alone.
When comparing the two elements \(Si\) and \(Tl\), the larger element is \(Tl\) based on periodic trends alone.
When comparing the two elements \(Sn\) and \(C\), the larger element is \(Sn\) based on periodic trends alone.