Question

check your theoretical yield mass. check your yield calculation. did you report your data to the correct number of significant figures? saponification triglyceride name palmitin triglyceride molecular formula $c_{51}h_{98}o_{6}$ triglyceride molar mass (g/mol) 807.29 mass of triglyceride (g) 4.13 soap name sodium palmitate soap molecular formula $nac_{16}h_{31}o_{2}$ soap molar mass (g/mol) 278.40 mass of filter paper (g) 0.23 mass of filter paper + soap (g) 3.56 mass of soap (g) 3.33 theoretical yield (g) actual yield (g) 3.33 percent yield (%) ph of soap solution

Explanation:

Step1: Determine moles of triglyceride

Use the formula $n=\frac{m}{M}$, where $n$ is the number of moles, $m$ is the mass and $M$ is the molar - mass. Given $m = 4.13$ g and $M=807.29$ g/mol.
$n_{triglyceride}=\frac{4.13}{807.29}\text{ mol}$

Step2: Determine mole - ratio in saponification reaction

In the saponification of a triglyceride, 1 mole of triglyceride produces 3 moles of soap.

Step3: Calculate moles of soap produced theoretically

$n_{soap\ theoretical}=3\times n_{triglyceride}=3\times\frac{4.13}{807.29}\text{ mol}$

Step4: Calculate theoretical yield of soap

Use the formula $m = n\times M$. Given $M_{soap}=278.40$ g/mol.
$m_{theoretical}=n_{soap\ theoretical}\times278.40=3\times\frac{4.13}{807.29}\times278.40$
$m_{theoretical}=3\times\frac{4.13\times278.40}{807.29}=\frac{3\times4.13\times278.40}{807.29}\approx4.27$ g

Step5: Calculate percent yield

Percent yield is given by the formula $\text{Percent yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times100\%$. Given actual yield = 3.33 g and theoretical yield $\approx4.27$ g.
$\text{Percent yield}=\frac{3.33}{4.27}\times100\%\approx78.0\%$

Answer:

Theoretical yield: 4.27 g
Percent yield: 78.0%