QUESTION IMAGE
Question
- check the box if the statement describes the balanced or unbalanced for the equations.
4sb + 3o₃ → sb₄o₆
sio₂ + hf → sif₄ + h₂o
h₃aso₄ → as₂o₅ + h₂o
ch₄ + 2o₂ → co₂ + 2h₂o
co₂ + nh₃ → oc + h₂o
To determine if each chemical equation is balanced, we check the number of each atom on both sides of the arrow.
Equation 1: $\boldsymbol{4\text{Sb} + 3\text{O}_2
ightarrow \text{Sb}_4\text{O}_6}$
- Sb atoms: Left side has $4$ Sb, right side has $4$ Sb (balanced).
- O atoms: Left side: $3 \times 2 = 6$ O; Right side: $6$ O (balanced).
Thus, this equation is Balanced.
Equation 2: $\boldsymbol{\text{SiO}_2 + \text{HF}
ightarrow \text{SiF}_4 + \text{H}_2\text{O}}$
- Si atoms: Left side has $1$ Si, right side has $1$ Si (balanced).
- O atoms: Left side has $2$ O, right side has $1$ O (unbalanced).
Thus, this equation is Unbalanced.
Equation 3: $\boldsymbol{\text{H}_3\text{AsO}_4
ightarrow \text{As}_2\text{O}_5 + \text{H}_2\text{O}}$
- As atoms: Left side has $1$ As, right side has $2$ As (unbalanced).
Thus, this equation is Unbalanced.
Equation 4: $\boldsymbol{\text{CH}_4 + 2\text{O}_2
ightarrow \text{CO}_2 + 2\text{H}_2\text{O}}$
- C atoms: Left side has $1$ C, right side has $1$ C (balanced).
- H atoms: Left side: $4$ H; Right side: $2 \times 2 = 4$ H (balanced).
- O atoms: Left side: $2 \times 2 = 4$ O; Right side: $2 + 2 \times 1 = 4$ O (balanced).
Thus, this equation is Balanced.
Equation 5: $\boldsymbol{\text{CO}_2 + \text{NH}_3
ightarrow \text{OC} + \text{H}_2\text{O}}$
- C atoms: Left side has $1$ C, right side has $1$ C (balanced).
- O atoms: Left side has $2$ O, right side has $1$ O (unbalanced).
- N atoms: Left side has $1$ N, right side has $0$ N (unbalanced).
Thus, this equation is Unbalanced.
Final Answers (Check the boxes):
| Equation | Balanced | Unbalanced |
|---|
| $4\text{Sb} + 3\text{O}_2
ightarrow \text{Sb}_4\text{O}_6$ | $\boldsymbol{\checkmark}$ | |
| $\text{SiO}_2 + \text{HF}
ightarrow \text{SiF}_4 + \text{H}_2\text{O}$ | | $\boldsymbol{\checkmark}$ |
| $\text{H}_3\text{AsO}_4
ightarrow \text{As}_2\text{O}_5 + \text{H}_2\text{O}$ | | $\boldsymbol{\checkmark}$ |
| $\text{CH}_4 + 2\text{O}_2
ightarrow \text{CO}_2 + 2\text{H}_2\text{O}$ | $\boldsymbol{\checkmark}$ | |
| $\text{CO}_2 + \text{NH}_3
ightarrow \text{OC} + \text{H}_2\text{O}$ | | $\boldsymbol{\checkmark}$ |
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
To determine if each chemical equation is balanced, we check the number of each atom on both sides of the arrow.
Equation 1: $\boldsymbol{4\text{Sb} + 3\text{O}_2
ightarrow \text{Sb}_4\text{O}_6}$
- Sb atoms: Left side has $4$ Sb, right side has $4$ Sb (balanced).
- O atoms: Left side: $3 \times 2 = 6$ O; Right side: $6$ O (balanced).
Thus, this equation is Balanced.
Equation 2: $\boldsymbol{\text{SiO}_2 + \text{HF}
ightarrow \text{SiF}_4 + \text{H}_2\text{O}}$
- Si atoms: Left side has $1$ Si, right side has $1$ Si (balanced).
- O atoms: Left side has $2$ O, right side has $1$ O (unbalanced).
Thus, this equation is Unbalanced.
Equation 3: $\boldsymbol{\text{H}_3\text{AsO}_4
ightarrow \text{As}_2\text{O}_5 + \text{H}_2\text{O}}$
- As atoms: Left side has $1$ As, right side has $2$ As (unbalanced).
Thus, this equation is Unbalanced.
Equation 4: $\boldsymbol{\text{CH}_4 + 2\text{O}_2
ightarrow \text{CO}_2 + 2\text{H}_2\text{O}}$
- C atoms: Left side has $1$ C, right side has $1$ C (balanced).
- H atoms: Left side: $4$ H; Right side: $2 \times 2 = 4$ H (balanced).
- O atoms: Left side: $2 \times 2 = 4$ O; Right side: $2 + 2 \times 1 = 4$ O (balanced).
Thus, this equation is Balanced.
Equation 5: $\boldsymbol{\text{CO}_2 + \text{NH}_3
ightarrow \text{OC} + \text{H}_2\text{O}}$
- C atoms: Left side has $1$ C, right side has $1$ C (balanced).
- O atoms: Left side has $2$ O, right side has $1$ O (unbalanced).
- N atoms: Left side has $1$ N, right side has $0$ N (unbalanced).
Thus, this equation is Unbalanced.
Final Answers (Check the boxes):
| Equation | Balanced | Unbalanced |
|---|
| $4\text{Sb} + 3\text{O}_2
ightarrow \text{Sb}_4\text{O}_6$ | $\boldsymbol{\checkmark}$ | |
| $\text{SiO}_2 + \text{HF}
ightarrow \text{SiF}_4 + \text{H}_2\text{O}$ | | $\boldsymbol{\checkmark}$ |
| $\text{H}_3\text{AsO}_4
ightarrow \text{As}_2\text{O}_5 + \text{H}_2\text{O}$ | | $\boldsymbol{\checkmark}$ |
| $\text{CH}_4 + 2\text{O}_2
ightarrow \text{CO}_2 + 2\text{H}_2\text{O}$ | $\boldsymbol{\checkmark}$ | |
| $\text{CO}_2 + \text{NH}_3
ightarrow \text{OC} + \text{H}_2\text{O}$ | | $\boldsymbol{\checkmark}$ |