Question

chalcopyrite, the principal ore of copper (cu), contains 34.63% cu by mass. how many grams of cu can be obtained from 1.08 × 10^4 kg of the ore? round your answer to 3 significant digits.

Explanation:

Step1: Convert the mass of the ore to grams

Since \(1\space kg = 1000\space g\), then \(1.08\times10^{4}\space kg=1.08\times 10^{4}\times10^{3}\space g = 1.08\times10^{7}\space g\)

Step2: Calculate the mass of Cu

The mass percentage of \(Cu\) is \(34.63\%\), which can be written as \(0.3463\) in decimal form.
The mass of \(Cu\) is \(m = 0.3463\times1.08\times 10^{7}\space g\)

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Step3: Round to 3 significant digits

Rounding \(3.74004\times 10^{6}\space g\) to 3 significant digits gives \(3.74\times10^{6}\space g\)

Answer:

\(3.74\times 10^{6}\)