Question

categorize the following bonded atom types in the appropriate bond classifications. hint: calculate the difference in electronegativity for each pair of bonded atoms. nonpolar covalent bond no answers chosen polar covalent bond no answers chosen ionic bond no answers chosen possible answers ba - cl s - o cs - br p - f al - cl n - n

Explanation:

Step1: Recall electronegativity values

Look up electronegativity values of Ba (0.89), Cl (3.16), S (2.58), O (3.44), Cs (0.79), Br (2.96), P (2.19), F (3.98), Al (1.61), N (3.04).

Step2: Calculate electronegativity differences

For Ba - Cl: $|3.16 - 0.89|=2.27$.
For S - O: $|3.44 - 2.58| = 0.86$.
For Cs - Br: $|2.96 - 0.79|=2.17$.
For P - F: $|3.98 - 2.19| = 1.79$.
For Al - Cl: $|3.16 - 1.61|=1.55$.
For N - N: $|3.04 - 3.04| = 0$.

Step3: Classify bonds

Non - polar covalent bonds have electronegativity difference close to 0. So N - N is non - polar covalent.
Polar covalent bonds have electronegativity difference between 0.5 - 1.9. So S - O, P - F, Al - Cl are polar covalent.
Ionic bonds have electronegativity difference > 1.9. So Ba - Cl and Cs - Br are ionic.

Answer:

Nonpolar Covalent Bond: N - N
Polar Covalent Bond: S - O, P - F, Al - Cl
Ionic Bond: Ba - Cl, Cs - Br