Question

carbon tetrabromide (cbr₄) is a component of some fire - resistant substances. it is produced when methane gas (ch₄) and bromine gas (br₂) react in the presence of uv light. this reaction is represented by the balanced chemical equation below.
ch₄(g)+4br₂(g)→cbr₄(s)+4hbr(g)
determine the number of each type of atom in the reactants and products.

Explanation:

Step1: Count H atoms in reactants

In \(CH_4\), there are 4 H atoms.

Step2: Count H atoms in products

In \(4HBr\), \(4\times1 = 4\) H atoms.

Step3: Count Br atoms in reactants

In \(4Br_2\), \(4\times2=8\) Br atoms.

Step4: Count Br atoms in products

In \(CBr_4\) there are 4 Br atoms, and in \(4HBr\) there are \(4\times1 = 4\) Br atoms. Total \(4 + 4=8\) Br atoms.

Answer:

	Number of atoms in reactants	Number of atoms in products
Br	8	8