Question

calculate the percent composition of the elements in $mgso_4$ and $c_6h_{12}o_6$. carbon comprises approximately select of $c_6h_{12}o_6$. magnesium comprises approxima select of $mgso_4$. sulfur comprises approximately select of $mgso_4$. hydrogen comprises approximately select of $c_6h_{12}o_6$.

Explanation:

Step1: Calculate molar mass of \(C_6H_{12}O_6\)

Atomic mass of \(C = 12.01\space g/mol\), \(H=1.008\space g/mol\), \(O = 16.00\space g/mol\)
\(M_{C_6H_{12}O_6}=6\times12.01 + 12\times1.008+6\times16.00\)
\(=72.06+12.096 + 96\)
\(=180.156\space g/mol\)
Mass of carbon in \(C_6H_{12}O_6\): \(m_C=6\times12.01 = 72.06\space g/mol\)
Percent of carbon: \(\frac{72.06}{180.156}\times100\%\approx40.0\%\)

Step2: Calculate molar mass of \(MgSO_4\)

Atomic mass of \(Mg = 24.31\space g/mol\), \(S = 32.07\space g/mol\), \(O=16.00\space g/mol\)
\(M_{MgSO_4}=24.31+32.07 + 4\times16.00\)
\(=24.31+32.07+64\)
\(=120.38\space g/mol\)
Mass of magnesium in \(MgSO_4\): \(m_{Mg}=24.31\space g/mol\)
Percent of magnesium: \(\frac{24.31}{120.38}\times100\%\approx20.2\%\)
Mass of sulfur in \(MgSO_4\): \(m_S = 32.07\space g/mol\)
Percent of sulfur: \(\frac{32.07}{120.38}\times100\%\approx26.6\%\)

Step3: Calculate percent of hydrogen in \(C_6H_{12}O_6\)

Mass of hydrogen in \(C_6H_{12}O_6\): \(m_H=12\times1.008 = 12.096\space g/mol\)
Percent of hydrogen: \(\frac{12.096}{180.156}\times100\%\approx6.7\%\)

Answer:

Carbon comprises approximately \(40.0\%\) of \(C_6H_{12}O_6\).
Magnesium comprises approximately \(20.2\%\) of \(MgSO_4\).
Sulfur comprises approximately \(26.6\%\) of \(MgSO_4\).
Hydrogen comprises approximately \(6.7\%\) of \(C_6H_{12}O_6\).