Question

1. calculate the molarity of a solution that contains 0.0289 mol k2so4 in 500.0 ml of solution.

a. 5.78×10−5 m
b. 0.0145 m
c. 0.0578 m
d. 0.145 m
e. 1.45 m

1. what volume of 2.50 m naoh (40.00 g/mol) contains 0.100 mole of naoh?

a. 0.250 l
b. 40.0 ml
c. 25.0 ml
d. 0.250 ml
e. 0.0400 ml

1. what volume of 12.0 m hcl solution needs to be diluted to produce 500.0 ml of 3.00 m hcl solution?

a. 0.125 l
b. 0.250 l
c. 0.500 l
d. 2.00 l
e. 1.00 l

Explanation:

Step1: Recall the formula for molarity

Molarity ($M$) is defined as $M=\frac{n}{V}$, where $n$ is the number of moles of solute and $V$ is the volume of the solution in liters.

Step2: Convert the volume from milliliters to liters

Given $V = 500.0\space mL$. Since $1\space L=1000\space mL$, then $V=\frac{500.0}{1000} = 0.5000\space L$.

Step3: Substitute the values into the molarity formula

We have $n = 0.0289\space mol$ and $V=0.5000\space L$. So, $M=\frac{0.0289\space mol}{0.5000\space L}=0.0578\space M$.

Answer:

C. $0.0578\space M$