Question

calculate the molar mass of oxalic acid dihydrate (h₂c₂o₄·2h₂o). g/mol

Explanation:

Step1: Determine the molar mass of each element

The molar mass of \(H\) is \(1.008\ g/mol\), \(C\) is \(12.01\ g/mol\), and \(O\) is \(16.00\ g/mol\).

Step2: Calculate the molar mass of \(H_2C_2O_4\)

For \(H_2C_2O_4\):

• There are \(2\) \(H\) atoms: \(2\times1.008 = 2.016\ g/mol\)
• There are \(2\) \(C\) atoms: \(2\times12.01=24.02\ g/mol\)
• There are \(4\) \(O\) atoms: \(4\times16.00 = 64.00\ g/mol\)

The molar mass of \(H_2C_2O_4\) is \(2.016 + 24.02+64.00=90.036\ g/mol\)

Step3: Calculate the molar mass of \(2H_2O\)

For \(H_2O\), molar mass of one \(H_2O\) is \(2\times1.008+16.00 = 18.016\ g/mol\)
For \(2H_2O\), it is \(2\times18.016 = 36.032\ g/mol\)

Step4: Calculate the molar mass of \(H_2C_2O_4\cdot2H_2O\)

Add the molar mass of \(H_2C_2O_4\) and \(2H_2O\):
\(90.036+36.032 = 126.068\ g/mol\)

Answer:

\(126.07\ g/mol\) (rounded to two decimal places)