Question

calculate the molar concentration a solution containing 3.0 moles of nacl in 1405 milliliters of water.

Explanation:

Step1: Convert volume to liters

Since \(1\space L = 1000\space mL\), then \(V=1405\space mL=\frac{1405}{1000}\space L = 1.405\space L\)

Step2: Use molarity formula

Molarity \(M=\frac{n}{V}\), where \(n = 3.0\space mol\) (moles of solute) and \(V = 1.405\space L\) (volume of solution). So \(M=\frac{3.0\space mol}{1.405\space L}\approx2.135\space mol/L\)

Answer:

\(2.14\space molar\) (rounded to two decimal places)