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4. —caf_{2}+—li_{2}so_{4}→—caso_{4}+—lif

Question

  1. —caf_{2}+—li_{2}so_{4}→—caso_{4}+—lif

Explanation:

Step1: Balance the chemical equation

According to the law of conservation of mass, the number of atoms of each element on both sides of the chemical equation should be equal.
For the reaction \(CaF_{2}+Li_{2}SO_{4}\to CaSO_{4}+LiF\), we can see that on the left - hand side, there are 2 \(Li\) atoms in \(Li_{2}SO_{4}\) and 1 \(Li\) atom in \(LiF\) on the right - hand side, and 2 \(F\) atoms in \(CaF_{2}\) and 1 \(F\) atom in \(LiF\) on the right - hand side.
We can balance the equation by putting a coefficient of 2 in front of \(LiF\).

Answer:

\(CaF_{2}+Li_{2}SO_{4}\to CaSO_{4}+2LiF\)