Question

based on the positions of the atoms in the periodic table, arrange the following bonds in order of bond length.
items (5 items)
(drag and drop into the appropriate area)
h - at
h - cl
h - i
h - br
h - f

Explanation:

Bond length is related to the atomic radius of the atoms forming the bond. As we move down a group in the periodic table, the atomic radius increases. For the hydrogen - halogen bonds (H - X, where X is a halogen), the atomic radius of halogens increases in the order \(F\lt Cl\lt Br\lt I\lt At\). A smaller atomic radius leads to a shorter bond length. So, the bond length of \(H - F\) is the shortest among these bonds as fluorine has the smallest atomic radius among the given halogens.

Answer:

1. \(H - F\)