Question

based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation: ( )li₂o + ( )h₂o → ( )lioh

Explanation:

Step1: Analyze Li atoms

On the left, \( \text{Li}_2\text{O} \) has 2 Li atoms. On the right, \( \text{LiOH} \) has 1 Li atom. So we need a coefficient of 2 for \( \text{LiOH} \) to balance Li: \( \text{Li}_2\text{O} + \text{H}_2\text{O}
ightarrow 2\text{LiOH} \).

Step2: Analyze O and H atoms

Now, check O and H. Left: \( \text{Li}_2\text{O} \) has 1 O, \( \text{H}_2\text{O} \) has 1 O (total 2 O). Right: \( 2\text{LiOH} \) has 2 O (1 per \( \text{LiOH} \times 2 \)). For H: Left \( \text{H}_2\text{O} \) has 2 H, right \( 2\text{LiOH} \) has 2 H (1 per \( \text{LiOH} \times 2 \)). So coefficients are 1 for \( \text{Li}_2\text{O} \), 1 for \( \text{H}_2\text{O} \), 2 for \( \text{LiOH} \).

Answer:

1 (for \( \text{Li}_2\text{O} \)), 1 (for \( \text{H}_2\text{O} \)), 2 (for \( \text{LiOH} \))