Question

based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation: (\boldsymbol{\sim})na₂hpo₄ → (\boldsymbol{\sim})na₄p₂o₇ + (\boldsymbol{\sim})h₂o

Explanation:

Step1: Balance Na atoms

On the left: 2 Na (in $\ce{Na2HPO4}$). On the right: 4 Na (in $\ce{Na4P2O7}$). So we need to multiply $\ce{Na2HPO4}$ by 2 to make Na atoms 4 (2×2 = 4). Now the equation is $2\ce{Na2HPO4}
ightarrow \ce{Na4P2O7} + \ce{H2O}$.

Step2: Balance P atoms

Left: 2 P (2×1). Right: 2 P (in $\ce{Na4P2O7}$). P is balanced.

Step3: Balance O and H atoms

Left: O - 2×4 = 8; H - 2×1 = 2.
Right: O in $\ce{Na4P2O7}$ is 7, O in $\ce{H2O}$ is 1 (total 8); H in $\ce{H2O}$ is 2. So H and O are balanced with 1 $\ce{H2O}$.

Answer:

2, 1, 1 (coefficients for $\ce{Na2HPO4}$, $\ce{Na4P2O7}$, $\ce{H2O}$ respectively)