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balance the reaction, do not leave any fractions, dont leave anything b…

Question

balance the reaction, do not leave any fractions, dont leave anything blank, then answer the questions about the reaction
1 mg(oh)₂ + 2 h₃po₄ → 3 mg₃(po₄)₂ + 4 h₂o
this is an 5 reaction and also a 6 reaction (in the order given in the answers).
is this a redox reaction? (yes/no)7, because neither mg⁺², po₄⁻³, h⁺¹, nor oh⁻¹ change oxidation state.
will the reaction happen as it is written? (yes/no)8, because acids and bases are reactive and because h₂o is 9. the reverse reaction would not happen.
a. 1 b. 2 c. 3 d. 4 e. 5 f. 6 g. 7 h. 8
i. 9 j. 10 k. 12 l. 14 m. 16 n. 18 o. 20 p. 21
q. 24 r. 26 s. 28 t. synthesis u. decomposition
v. single displacement w. double displacement x. neutralization
y. combustion z. yes aa. no bb. reactive cc. stable
dd. oxidized ee. reduced

Explanation:

Step1: Balance Mg atoms

On the right - hand side, there are 3 Mg atoms in \(Mg_3(PO_4)_2\). So, we put a coefficient of 3 in front of \(Mg(OH)_2\) on the left - hand side.
\(3Mg(OH)_2 + 2H_3PO_4
ightarrow Mg_3(PO_4)_2+6H_2O\)

Step2: Balance P atoms

There are 2 P atoms in \(H_3PO_4\) and 2 P atoms in \(Mg_3(PO_4)_2\).

Step3: Balance O and H atoms

For \(Mg(OH)_2\): 3 moles of \(Mg(OH)_2\) have \(3\times2 = 6\) OH⁻ groups. 2 moles of \(H_3PO_4\) have \(2\times3=6\) H⁺ groups. The reaction between OH⁻ and H⁺ gives \(H_2O\). The number of \(H_2O\) molecules is 6.

For the reaction type:

  • It is a neutralization reaction (\(X\)) because an acid (\(H_3PO_4\)) reacts with a base (\(Mg(OH)_2\)) to form salt (\(Mg_3(PO_4)_2\)) and water.
  • It is also a double - displacement reaction (\(W\)) as the ions (\(Mg^{2 +}\), \(OH^{-}\), \(H^{+}\), \(PO_4^{3-}\)) exchange their partners.

For the redox reaction question:

  • In a redox reaction, there is a change in oxidation states. Since \(Mg^{2+}\), \(PO_4^{3 -}\), \(H^{+}\), and \(OH^{-}\) do not change their oxidation states, the answer is \(AA\) (no).

For the reaction occurrence question:

  • Acids and bases are reactive. \(H_2O\) is stable (\(CC\)). So the reaction will happen (\(Z\)).

Answer:

  1. \(3\)
  2. \(2\)
  3. \(1\)
  4. \(6\)
  5. \(X\) (neutralization)
  6. \(W\) (double displacement)
  7. \(AA\) (no)
  8. \(Z\) (yes)
  9. \(CC\) (stable)