Question

balance the following equation:

hcl + naoh→nacl + h₂o

when the equation is properly balanced, the correct coefficients are, respectively

Explanation:

Step1: Count atoms on both sides

Reactants: 1 H (from HCl), 1 Cl, 1 Na, 1 O (from NaOH), 1 H (from NaOH). Products: 1 Na, 1 Cl, 2 H (from H₂O), 1 O.

Step2: Adjust coefficients

Let's start with H. On the left, we have \(1 + 1=2\) H (from HCl and NaOH). On the right, we have 2 H in \(H_2O\). For Cl: 1 on left (HCl) and 1 on right (NaCl). For Na: 1 on left (NaOH) and 1 on right (NaCl). For O: 1 on left (NaOH) and 1 on right (\(H_2O\)). So if we put coefficient 1 for each compound: \(1HCl+1NaOH
ightarrow1NaCl + 1H_2O\)

Answer:

1, 1, 1, 1