Question

balance the following equation:

$\ce{\\_\\_h_{2}so_{4} + \\_\\_bacl_{2} \
ightarrow \\_\\_baso_{4} + \\_\\_hcl}$

when the equation is properly balanced, the correct coefficients are, respectively

Explanation:

Step1: Balance the Ba atoms

The number of Ba atoms on both sides is already 1. So no coefficient change for Ba - containing compounds.

Step2: Balance the SO₄²⁻ groups

The number of SO₄²⁻ groups on both sides is already 1. So no coefficient change for SO₄²⁻ - containing compounds.

Step3: Balance the Cl atoms

On the left - hand side, there are 2 Cl atoms in BaCl₂. On the right - hand side, HCl has 1 Cl atom. So we put a coefficient of 2 in front of HCl: \(H_{2}SO_{4}+BaCl_{2}\to BaSO_{4}+2HCl\)

Step4: Check H atoms

On the left - hand side, there are 2 H atoms in H₂SO₄. On the right - hand side, in 2HCl, there are \(2\times1 = 2\) H atoms.

Answer:

1, 1, 1, 2