Question

1. balance the equation for propane (c₃h₈) is burned, by dragging coefficients.

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c₃h₈ + o₂ → co₂ + h₂o
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Explanation:

Step1: Balance Carbon atoms

Propane ($\ce{C3H8}$) has 3 C atoms, so we need 3 $\ce{CO2}$ to balance C. So coefficient of $\ce{CO2}$ is 3.

Step2: Balance Hydrogen atoms

Propane has 8 H atoms. Each $\ce{H2O}$ has 2 H, so number of $\ce{H2O}$ is $\frac{8}{2}=4$. So coefficient of $\ce{H2O}$ is 4.

Step3: Balance Oxygen atoms

On right side, $\ce{CO2}$ has 3×2 = 6 O, $\ce{H2O}$ has 4×1 = 4 O, total O is 6 + 4 = 10. Each $\ce{O2}$ has 2 O, so number of $\ce{O2}$ is $\frac{10}{2}=5$. So coefficient of $\ce{O2}$ is 5.

Step4: Propane coefficient

Since we start with 1 $\ce{C3H8}$ (as it's the reactant and we balance around it), its coefficient is 1.

Answer:

The balanced equation is $\boldsymbol{1\ce{C3H8} + 5\ce{O2}
ightarrow 3\ce{CO2} + 4\ce{H2O}}$