Question

balance this equation. _cf₄ + _br₂ → _cbr₄ + _f₂

Explanation:

Step1: Count atoms on both sides

For \(C\): 1 on left and 1 on right.
For \(F\): 4 on left (in \(CF_4\)) and 2 on right (in \(F_2\)).
For \(Br\): 2 on left (in \(Br_2\)) and 4 on right (in \(CBr_4\)).

Step2: Balance \(Br\) atoms

Put 2 in front of \(Br_2\) (left side). Now \(Br\) atoms: \(2\times2 = 4\) (left) and 4 (right).

Step3: Balance \(F\) atoms

Put 2 in front of \(F_2\) (right side). Now \(F\) atoms: 4 (left) and \(2\times2=4\) (right).

Answer:

1, 2, 1, 2 (i.e., \(1CF_4 + 2Br_2=1CBr_4 + 2F_2\))