Question

arrange the highlighted bonds in the table below in decreasing order of polarity. that is, pick 1 for the most polar bond, 2 for the next most polar bond, and so on.

bond	polarity
h—i:	select
h—f:	select

Explanation:

Step1: Recall electronegativity concept

Polarity of a bond depends on electronegativity difference. Higher the difference, more polar the bond. The electronegativity values are: H = 2.2, Cl = 3.16, I = 2.66, F = 3.98.

Step2: Calculate electronegativity differences

For H - Cl: $\Delta\chi=3.16 - 2.2=0.96$. For H - I: $\Delta\chi=2.66 - 2.2 = 0.46$. For H - F: $\Delta\chi=3.98 - 2.2=1.78$.

Step3: Arrange in decreasing order

Since 1.78>0.96>0.46, the order of bond polarity is H - F > H - Cl > H - I. So H - F is 1, H - Cl is 2, H - I is 3.

Answer:

H—F: 1
H—Cl: 2
H—I: 3