Question

for an aqueous solution of sucrose (c12h22o11), calculate the volume, in l, of a 0.125 m solution that would contain 3.90 moles of sucrose. report your answer using the correct number of significant figures.

Explanation:

Step1: Use the formula for molarity

The formula for molarity \(M=\frac{n}{V}\), where \(M\) is molarity, \(n\) is the number of moles, and \(V\) is the volume in liters. We need to solve for \(V\), so we can re - arrange the formula to \(V = \frac{n}{M}\).

Step2: Substitute the given values

We are given that \(n = 3.90\) moles and \(M=0.125\) M. Substituting these values into the formula \(V=\frac{n}{M}\), we get \(V=\frac{3.90}{0.125}\).

Step3: Calculate the volume

\(V=\frac{3.90}{0.125}=31.2\) L

Answer:

\(31.2\) L