Question

answer the following related to the solubility graph

a) if 60 g of substance b is dissolved in 100 g of water, at what
temperature will the solution be saturated?

b) how many grams of substance c dissolved in 50 g of water at
35°c will create a saturated solution?

Explanation:

Part (a)

Step 1: Analyze the solubility graph for substance B

We need to find the temperature at which the solubility of substance B is 60 g per 100 g of water. Looking at the graph for substance B (the dashed line with dots), we find the point where the solubility is 60 g/100 g water.

Step 2: Determine the temperature

From the graph, when the solubility of B is 60 g in 100 g water, the corresponding temperature is 60°C.

Step 1: Find the solubility of substance C at 35°C

First, we look at the solubility graph for substance C (the dashed line). At 35°C, the solubility of C in 100 g of water is 20 g (since at 30°C it's 20 g, and 35°C is close, and from the graph, at 35°C, the solubility of C is 20 g per 100 g water).

Step 2: Calculate the solubility in 50 g of water

Since the solubility in 100 g water is 20 g, in 50 g water (which is half of 100 g), the solubility will be half of 20 g. So, $\frac{20\ g}{100\ g\ water} \times 50\ g\ water = 10\ g$.

Answer:

60°C

Part (b)