Question

aluminum metal reacts with gaseous chlorine to give solid aluminum chloride. the correct balanced equation for this reaction with all the formulas written correctly would be 1) al(s) + cl₂(g) → alcl₂(s) 2) al(s) + cl(g)→ alcl(s) 3) al(s) + 3cl₂(g)→ 2alcl₃(s) 4) 2al(s) + 3cl₂(g)→ 2alcl₃(s)

Explanation:

Step1: Analyze Reactants and Products

Reactants: Aluminum (Al, solid) and Chlorine (Cl₂, gaseous, since chlorine is diatomic). Product: Aluminum Chloride (AlCl₃, solid, as aluminum has a +3 charge and chlorine -1, so formula is AlCl₃).

Step2: Check Formula Validity

• Option 1: Product is AlCl₂, incorrect formula (Al should be +3, Cl -1, so AlCl₃). Eliminate.
• Option 2: Chlorine is written as Cl (not diatomic), incorrect. Eliminate.
• Option 3: Left Al: 1, Right Al: 2 (unbalanced). Left Cl: \(3\times2 = 6\), Right Cl: \(2\times3 = 6\) (Cl balanced, but Al unbalanced). Eliminate.
• Option 4: Left Al: 2, Right Al: 2. Left Cl: \(3\times2 = 6\), Right Cl: \(2\times3 = 6\). Formulas correct (Al, Cl₂, AlCl₃) and equation balanced.

Answer:

1. \(2\text{Al}(s) + 3\text{Cl}_2(g)

ightarrow 2\text{AlCl}_3(s)\)