Question

1. al₂(so₄)₃ + bacl₂ → baso₄ + alcl₃
2. nh₃ → h₂ + n₂

Explanation:

Step1: Balance the first equation

We need to balance the atoms on both sides of the equation $Al_2(SO_4)_3 + BaCl_2
ightarrow BaSO_4+AlCl_3$.
For the sulfate - $SO_4$ groups, there are 3 on the left - hand side and 1 on the right - hand side. For the aluminum atoms, there are 2 on the left and 1 on the right. For the barium and chlorine atoms, we adjust the coefficients accordingly.
The balanced equation is $Al_2(SO_4)_3 + 3BaCl_2 = 3BaSO_4+2AlCl_3$.

Step2: Balance the second equation

For the equation $NH_3
ightarrow H_2 + N_2$, we balance the nitrogen and hydrogen atoms. There is 1 nitrogen atom on the left and 2 on the right, and 3 hydrogen atoms on the left and 2 on the right.
The balanced equation is $2NH_3 = 3H_2+N_2$.

Answer:

1. $Al_2(SO_4)_3 + 3BaCl_2 = 3BaSO_4+2AlCl_3$
2. $2NH_3 = 3H_2+N_2$