Question

1. ag + kno₃ → nr
2. zn + agno₃ →
3. al + h₂so₄ →
4. cl₂ + ki→
5. li + h₂o →
6. cu + feso₄ →
7. na + h₂o →
8. fe + pb(no₃)₂ →
9. cu + h₂o →
10. cu + al₂(so₄) →

Explanation:

Step1: Analyze metal activity series

According to the metal activity series, a more active metal can displace a less active metal from its compound.

Step2: Write chemical equations

• For \(Zn + AgNO_3\): \(Zn\) is more active than \(Ag\), so \(Zn\) displaces \(Ag\) from \(AgNO_3\). The reaction is \(Zn + 2AgNO_3=Zn(NO_3)_2 + 2Ag\).
• For \(Al + H_2SO_4\): \(Al\) reacts with \(H_2SO_4\) to produce \(Al_2(SO_4)_3\) and \(H_2\). The reaction is \(2Al + 3H_2SO_4=Al_2(SO_4)_3 + 3H_2\uparrow\).
• For \(Cl_2+KI\): \(Cl_2\) is more active than \(I_2\), so \(Cl_2\) displaces \(I_2\) from \(KI\). The reaction is \(Cl_2 + 2KI = 2KCl+I_2\).
• For \(Li + H_2O\): \(Li\) reacts with \(H_2O\) to produce \(LiOH\) and \(H_2\). The reaction is \(2Li + 2H_2O = 2LiOH+H_2\uparrow\).
• For \(Na + H_2O\): \(Na\) reacts with \(H_2O\) to produce \(NaOH\) and \(H_2\). The reaction is \(2Na + 2H_2O = 2NaOH + H_2\uparrow\).
• For \(Fe + Pb(NO_3)_2\): \(Fe\) is more active than \(Pb\), so \(Fe\) displaces \(Pb\) from \(Pb(NO_3)_2\). The reaction is \(Fe+Pb(NO_3)_2 = Fe(NO_3)_2+Pb\).
• \(Ag + KNO_3\): \(Ag\) is less active than \(K\), so no reaction (\(NR\)).
• \(Cu + FeSO_4\): \(Cu\) is less active than \(Fe\), so no reaction (\(NR\)).
• \(Cu + H_2O\): \(Cu\) does not react with water under normal conditions (\(NR\)).
• \(Cu + Al_2(SO_4)_3\): \(Cu\) is less active than \(Al\), so no reaction (\(NR\)).

Answer:

1. \(NR\)
2. \(Zn + 2AgNO_3=Zn(NO_3)_2 + 2Ag\)
3. \(2Al + 3H_2SO_4=Al_2(SO_4)_3 + 3H_2\uparrow\)
4. \(Cl_2 + 2KI = 2KCl+I_2\)
5. \(2Li + 2H_2O = 2LiOH+H_2\uparrow\)
6. \(NR\)
7. \(2Na + 2H_2O = 2NaOH + H_2\uparrow\)
8. \(Fe+Pb(NO_3)_2 = Fe(NO_3)_2+Pb\)
9. \(NR\)
10. \(NR\)