Question

add either a zero or a positive or negative integer to each answer field. all input boxes need to be filled for the answer to be correct.

\\(\text{cl}_2\text{o}_2(g) \longrightarrow 2\text{clo}(g)\\)

reactant: product:

enter answer:

\\\frac{\box}{\box} \frac{\delta\text{cl}_2\text{o}_2}{\delta t} = \frac{\box}{\box} \frac{\delta\text{clo}}{\delta t}\\

part 2 (1 point)

\\(\text{n}_2\text{o}_5(g) \longrightarrow \text{no}_2(g) + \text{no}_3(g)\\)

reactant: product (\\(\text{no}_2\\)): product (\\(\text{no}_3\\)):

enter answer:

\\\frac{\box}{\box} \frac{\delta\text{n}_2\text{o}_5}{\delta t} = \frac{\box}{\box} \frac{\delta\text{no}_2}{\delta t} = \frac{\box}{\box} \frac{\delta\text{no}_3}{\delta t}\\

Explanation:

Relate reactant and product rates for Part 1

Using the Relative Rates of Reaction knowledge point

$$ \text{Reaction: } \text{Cl}_2\text{O}_2(g) \longrightarrow 2\text{ClO}(g) $$

$$ \text{Rate} = -\frac{\Delta[\text{Cl}_2\text{O}_2]}{\Delta t} = +\frac{1}{2}\frac{\Delta[\text{ClO}]}{\Delta t} $$

$$ \frac{-1}{1}\frac{\Delta[\text{Cl}_2\text{O}_2]}{\Delta t} = \frac{+1}{2}\frac{\Delta[\text{ClO}]}{\Delta t} $$

Relate reactant and product rates for Part 2

Using the Relative Rates of Reaction knowledge point

$$ \text{Reaction: } \text{N}_2\text{O}_5(g) \longrightarrow \text{NO}_2(g) + \text{NO}_3(g) $$

$$ \text{Rate} = -\frac{\Delta[\text{N}_2\text{O}_5]}{\Delta t} = +\frac{\Delta[\text{NO}_2]}{\Delta t} = +\frac{\Delta[\text{NO}_3]}{\Delta t} $$

$$ \frac{-1}{1}\frac{\Delta[\text{N}_2\text{O}_5]}{\Delta t} = \frac{+1}{1}\frac{\Delta[\text{NO}_2]}{\Delta t} = \frac{+1}{1}\frac{\Delta[\text{NO}_3]}{\Delta t} $$

Answer:

Question 1

For the reaction \(\text{Cl}_2\text{O}_2(g) \longrightarrow 2\text{ClO}(g)\):

$$ \frac{-1}{1}\frac{\Delta[\text{Cl}_2\text{O}_2]}{\Delta t} = \frac{+1}{2}\frac{\Delta[\text{ClO}]}{\Delta t} $$

Question 2

For the reaction \(\text{N}_2\text{O}_5(g) \longrightarrow \text{NO}_2(g) + \text{NO}_3(g)\):

$$ \frac{-1}{1}\frac{\Delta[\text{N}_2\text{O}_5]}{\Delta t} = \frac{+1}{1}\frac{\Delta[\text{NO}_2]}{\Delta t} = \frac{+1}{1}\frac{\Delta[\text{NO}_3]}{\Delta t} $$