Question

a 43.40 mg sample of an alcohol contains 15.10 mg of o, 22.60 mg of c, and 5.70 mg of h. what is its percent composition of oxygen?

Explanation:

Step1: Recall the formula for percent composition

Percent composition of a component \(=\frac{\text{Mass of component}}{\text{Total mass of sample}}\times100\%\)

Step2: Identify the mass of oxygen and total mass of sample

Mass of oxygen (\(m_O\)) \( = 15.10\space mg\), total mass of sample (\(m_{total}\)) \(=43.40\space mg\)

Step3: Substitute values into the formula

Percent composition of oxygen \(=\frac{15.10}{43.40}\times 100\%\)

$$
LATEXBLOCK0
$$

Answer:

\(34.8\%\)