Question

n₂ + 3h₂ → 2nh₃
how many grams of nitrogen,
n₂, would be required to create
9.3 moles ammonia, nh₃?
molar mass n₂: 28.02 g/mol
? g n₂

Explanation:

Step1: Find moles of \(N_2\)

From the balanced equation \(N_2 + 3H_2
ightarrow2NH_3\), the mole ratio of \(N_2\) to \(NH_3\) is \(1:2\).
If \(n(NH_3)=9.3\space mol\), then \(n(N_2)=\frac{1}{2}\times n(NH_3)\)
\(n(N_2)=\frac{1}{2}\times9.3\space mol = 4.65\space mol\)

Step2: Calculate mass of \(N_2\)

Use the formula \(m = n\times M\), where \(M(N_2) = 28.02\space g/mol\) and \(n(N_2)=4.65\space mol\)
\(m(N_2)=4.65\space mol\times28.02\space g/mol\)
\(m(N_2)=4.65\times28.02\space g\)
\(m(N_2)=130.3\space g\)

Answer:

\(130.3\space g\)