Question

32 formula 3 points
what is the boiling point, in $^{circ}c$, of an aqueous ethylene glycol solution, if the molality is 7.027 m? solve to the hundredth place. $t_{b}^{0}=100.00^{circ}c$ and $k_{f}=0.512^{circ}c/m$
answer

Explanation:

Step1: Calculate the boiling - point elevation

The formula for boiling - point elevation is \(\Delta T_b=K_bm\). Given \(K_b = 0.512^{\circ}C/m\) and \(m = 7.027m\).
\(\Delta T_b=0.512\times7.027\)

$$
LATEXBLOCK0
$$

Step2: Calculate the boiling point of the solution

The boiling point of the solution \(T_b=T_b^0+\Delta T_b\). Given \(T_b^0 = 100.00^{\circ}C\) and \(\Delta T_b=3.597824^{\circ}C\)
\(T_b=100.00 + 3.597824\)

Answer:

\(103.60^{\circ}C\)