QUESTION IMAGE
Question
- solve: |x - 5| = 9
- solve: -4(x + 3) + 2x = -18
- write the equation of a vertical line through (-2, 7)
- write the equation of a horizontal line through (0, -6)
- find x- and y-intercepts of 3x - 4y = 24
- graph 2x + 3y = 12 using intercepts method (label both intercepts)
- write the equation in slope-intercept form: passes through (0, -5), slope = 3
Problem 31: Solve \(|x - 5| = 9\)
Step 1: Recall absolute value definition
The absolute value equation \(|A| = B\) (where \(B \geq 0\)) implies \(A = B\) or \(A = -B\). So for \(|x - 5| = 9\), we have two cases:
Case 1: \(x - 5 = 9\)
Case 2: \(x - 5 = -9\)
Step 2: Solve Case 1
For \(x - 5 = 9\), add 5 to both sides:
\(x - 5 + 5 = 9 + 5\)
\(x = 14\)
Step 3: Solve Case 2
For \(x - 5 = -9\), add 5 to both sides:
\(x - 5 + 5 = -9 + 5\)
\(x = -4\)
Step 1: Distribute the -4
\(-4(x + 3) + 2x = -18\) becomes \(-4x - 12 + 2x = -18\)
Step 2: Combine like terms
Combine \(-4x\) and \(2x\): \(-2x - 12 = -18\)
Step 3: Add 12 to both sides
\(-2x - 12 + 12 = -18 + 12\)
\(-2x = -6\)
Step 4: Divide by -2
\(\frac{-2x}{-2} = \frac{-6}{-2}\)
\(x = 3\)
Step 1: Recall vertical line equation
A vertical line has an undefined slope and its equation is of the form \(x = a\), where \(a\) is the x - coordinate of any point on the line.
Step 2: Determine the value of \(a\)
The point \((-2, 7)\) has an x - coordinate of \(-2\). So the equation of the vertical line is \(x = -2\).
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\(x = 14\) or \(x = -4\)