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31. solve: |x - 5| = 9 32. solve: -4(x + 3) + 2x = -18 33. write the eq…

Question

  1. solve: |x - 5| = 9
  2. solve: -4(x + 3) + 2x = -18
  3. write the equation of a vertical line through (-2, 7)
  4. write the equation of a horizontal line through (0, -6)
  5. find x- and y-intercepts of 3x - 4y = 24
  6. graph 2x + 3y = 12 using intercepts method (label both intercepts)
  7. write the equation in slope-intercept form: passes through (0, -5), slope = 3

Explanation:

Problem 31: Solve \(|x - 5| = 9\)

Step 1: Recall absolute value definition

The absolute value equation \(|A| = B\) (where \(B \geq 0\)) implies \(A = B\) or \(A = -B\). So for \(|x - 5| = 9\), we have two cases:
Case 1: \(x - 5 = 9\)
Case 2: \(x - 5 = -9\)

Step 2: Solve Case 1

For \(x - 5 = 9\), add 5 to both sides:
\(x - 5 + 5 = 9 + 5\)
\(x = 14\)

Step 3: Solve Case 2

For \(x - 5 = -9\), add 5 to both sides:
\(x - 5 + 5 = -9 + 5\)
\(x = -4\)

Step 1: Distribute the -4

\(-4(x + 3) + 2x = -18\) becomes \(-4x - 12 + 2x = -18\)

Step 2: Combine like terms

Combine \(-4x\) and \(2x\): \(-2x - 12 = -18\)

Step 3: Add 12 to both sides

\(-2x - 12 + 12 = -18 + 12\)
\(-2x = -6\)

Step 4: Divide by -2

\(\frac{-2x}{-2} = \frac{-6}{-2}\)
\(x = 3\)

Step 1: Recall vertical line equation

A vertical line has an undefined slope and its equation is of the form \(x = a\), where \(a\) is the x - coordinate of any point on the line.

Step 2: Determine the value of \(a\)

The point \((-2, 7)\) has an x - coordinate of \(-2\). So the equation of the vertical line is \(x = -2\).

Answer:

\(x = 14\) or \(x = -4\)

Problem 32: Solve \(-4(x + 3) + 2x = -18\)