Question

if 30.0 l of oxygen gas is cooled from 473 k to 274 k at constant pressure, what is the new volume of oxygen?
o 17.4 l
o 60.0 l
o 51.8 l
o 0.150 l
o 23.0 l

Explanation:

Step1: Recall Charles's Law

Charles's Law is \( \frac{V_1}{T_1}=\frac{V_2}{T_2} \), where \( V_1 = 30.0\ L\), \( T_1=473\ K\), \( T_2 = 274\ K\), and \( V_2\) is the unknown.

Step2: Solve for \( V_2\)

Rearrange the formula to \( V_2=\frac{V_1\times T_2}{T_1}\).
Substitute the values: \( V_2=\frac{30.0\times274}{473}\).
Calculate \( 30.0\times274 = 8220\).
Then \( V_2=\frac{8220}{473}\approx17.4\ L\).

Answer:

17.4 L