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2n₂(g) + 5o₂(g) → 2n₂o₅(g) if 3.22 moles of n₂ react, what volume of n₂…

Question

2n₂(g) + 5o₂(g) → 2n₂o₅(g)
if 3.22 moles of n₂ react, what volume of n₂o₅ is produced at stp?
? l n₂o₅

Explanation:

Step1: Find mole ratio of N₂ to N₂O₅

From reaction: 2 mol N₂ → 2 mol N₂O₅, ratio = 1:1

Step2: Calculate moles of N₂O₅

Moles N₂O₅ = moles N₂ = 3.22 mol

Step3: Convert moles to volume at STP

Volume = moles × 22.4 L/mol = 3.22 × 22.4

Answer:

72.128 L