Question

24 multiple choice 2 points during the reaction of an alkene with a halogen in water (e.g., bromine in water), the major product is: an ether a dihalide a halohydrin an alcohol previous

Explanation:

Step1: Reaction mechanism

Alkene reacts with halogen in water.

Step2: Formation of halohydrin

First, a cyclic halonium ion forms. Then, water (as a nucleophile) attacks the more substituted carbon of the halonium ion. The result is a halohydrin (a compound with a halogen and a hydroxyl group on adjacent carbons). For example, when ethylene ($\ce{CH2=CH2}$) reacts with $\ce{Br2}$ in water, the major product is 2 - bromoethanol ($\ce{BrCH2CH2OH}$).
Ether formation would require an alkoxide nucleophile (not water in this reaction context). Dihalide formation would occur if there was no water (just the halogen, like in $\ce{CCl4}$ solvent). Alcohol formation in a simple addition to alkene (without halogen) would need a different reaction setup (like acid - catalyzed hydration of alkene, not halogen - water reaction).

Answer:

C. A halohydrin