Question

1. what is the mass percentage of the element carbon in a molecule of glucose (c₆h₁₂o₆)? enter the correct whole number in the box. %

Explanation:

Step1: Calculate molar mass of glucose

Molar mass of \( C_6H_{12}O_6 \) = (6×atomic mass of C) + (12×atomic mass of H) + (6×atomic mass of O).
Atomic masses: C = 12 g/mol, H = 1 g/mol, O = 16 g/mol.
So, molar mass = \( 6\times12 + 12\times1 + 6\times16 = 72 + 12 + 96 = 180 \) g/mol.

Step2: Calculate mass of carbon in glucose

Mass of C in \( C_6H_{12}O_6 \) = 6×12 = 72 g/mol.

Step3: Calculate mass percentage of C

Mass percentage = \( \frac{\text{Mass of C}}{\text{Molar mass of glucose}} \times 100 = \frac{72}{180} \times 100 = 40 \)%.

Answer:

40