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at 17°c, a 0.80 mole sample of a gas exerts a pressure of 1.2 atmospher…

Question

at 17°c, a 0.80 mole sample of a gas exerts a pressure of 1.2 atmospheres. what is the volume of the container?

Explanation:

Step1: Convert temperature to Kelvin

The formula to convert Celsius to Kelvin is \(T(K)=T(^{\circ}C)+273.15\). Given \(T = 17^{\circ}C\), then \(T=17 + 273.15=290.15K\).

Step2: Use the ideal gas law \(PV = nRT\)

We need to find \(V\), so we can rewrite the formula as \(V=\frac{nRT}{P}\).

  • The ideal - gas constant \(R = 0.0821\frac{L\cdot atm}{mol\cdot K}\)
  • \(n = 0.80mol\), \(T = 290.15K\), \(P = 1.2atm\)

Substitute the values into the formula: \(V=\frac{0.80\times0.0821\times290.15}{1.2}\)
First, calculate the numerator: \(0.80\times0.0821\times290.15=(0.80\times0.0821)\times290.15 = 0.06568\times290.15\approx19.06\)
Then, \(V=\frac{19.06}{1.2}\approx15.9L\)

Answer:

15.9 Liters