Question

1. predict the molecular shape of cf2cl2 (1 point) *

linear
bent
trigonal planar
trigonal pyramidal
tetrahedral

1. predict the molecular shape of h2co (1 point) *

linear
bent
trigonal planar
trigonal pyramidal
tetrahedral

Explanation:

Question 16:

Step1: Determine the central atom

The central atom in \( \text{CF}_2\text{Cl}_2 \) is carbon (C).

Step2: Calculate the number of electron groups

Carbon has 4 valence electrons. It forms single bonds with 2 F atoms and 2 Cl atoms, so there are 4 bonding electron groups (no lone pairs on C).

Step3: Predict the molecular shape

For a central atom with 4 bonding groups and no lone pairs, the electron - pair geometry and molecular shape are tetrahedral (based on VSEPR theory, \( \text{AX}_4 \) type, where A is the central atom and X are the surrounding atoms).

Step1: Determine the central atom

The central atom in \( \text{H}_2\text{CO} \) (formaldehyde) is carbon (C).

Step2: Calculate the number of electron groups

Carbon has 4 valence electrons. It forms a double bond with O and single bonds with 2 H atoms. The number of electron groups around C: the double bond counts as one electron group, and each single bond counts as one. So in total, there are 3 electron groups (all bonding, no lone pairs on C).

Step3: Predict the molecular shape

For a central atom with 3 bonding groups and no lone pairs ( \( \text{AX}_3 \) type in VSEPR theory), the molecular shape is trigonal planar.

Answer:

Tetrahedral (the option "Tetrahedral")

Question 17: