Question

16 multiple choice 1 point
if there are 5 moles of sodium and 8 moles of chlorine reacting to create table salt, nacl, what is the limiting reactant?
$2na(s) + cl_2(g) \longrightarrow 2nacl(s)$
\bigcirc nacl
\bigcirc none of these
\bigcirc $cl_2$
\bigcirc na

17 true or false 1 point
the state of matter is never included in chemical equations.
\bigcirc true
\bigcirc false

Explanation:

Question 16

Step1: Determine mole ratio

From the reaction \(2\text{Na}(s) + \text{Cl}_2(g)
ightarrow 2\text{NaCl}(s)\), the mole ratio of \(\text{Na}\) to \(\text{Cl}_2\) is \(2:1\).

Step2: Calculate required moles

For 5 moles of \(\text{Na}\), moles of \(\text{Cl}_2\) required = \(\frac{5}{2} = 2.5\) moles. We have 8 moles of \(\text{Cl}_2\), which is more than 2.5. For 8 moles of \(\text{Cl}_2\), moles of \(\text{Na}\) required = \(8\times2 = 16\) moles, but we only have 5 moles of \(\text{Na}\). So \(\text{Na}\) will be used up first.

Chemical equations often include the state of matter (e.g., \(s\) for solid, \(g\) for gas, \(l\) for liquid, \(aq\) for aqueous) to show the physical state of reactants and products. So the statement is false.

Answer:

D. Na (assuming the options are ordered as given: NaCl, none of these, Cl₂, Na)

Question 17